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12 teams- 6 different games; how do i get a different opponent for each game
Forum Home »  Questions & Answers »  12 teams- 6 different games; how do i get a different opponent for each game
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Rich Steward

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Posted: Fri May 27, 2011
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I'm trying to set up a tournament with 12 teams and 6 different games. There are 2 teams per game. I want each team to compete in each of the 6 games, but against a different team each time. So this is not a round robin tournament- each team will only play against 6 of the 11 other teams. Can someone figure out a rotation for this? Thanks!!!
POLSKAdoBOJU

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Posted: Sun May 29, 2011
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There are several different possibilities. Here are two:

Method 1:
Make two groups of six teams. A team plays all the teams in its group plus one team from the other group.

Method 2:
Number the teams from 1 to 12. All the even number teams play the odd number teams, and vice versa. So #1 plays 2, 4, 6, 8, 10 & 12. #2 would play 1, 3, 5, 7, 9, 11, etc...
Rich Steward

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Posted: Tue May 31, 2011
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Perfect- that works. Thanks so much for the help!
CoS

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Posted: Fri May 22, 2015
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I found these entry as I am searching for a solution to the same problem. Only that I don't understand how the six different games can take place at the same time. I have tried multiple ways but in the last round there are always two teams competing against another which have done so before.
So there are 12 teams and six games. I want each team to play against six others (for example method 2 or the teams 1-6 play against the teams 7-12). Each team should play all six different games and always have another partner! Can anybody help?
Pete

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Posted: Tue Jun 23, 2015
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Google for:
Howell Designs 29.1

What you are wanting is H(6,12).
Lena Avagyan
Posts: 3

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Posted: Tue Aug 1, 2017
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This allows us to conform to the following rules:

Every lettered team plays every numbered team exactly once - simply by design of the table
Every team plays every sport exactly once
Every team plays in every times lot exactly once

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